* 解题思路：先对nums2用单调栈求每个元素的下一个更大值，存入Map缓存；再遍历nums1直接查Map得结果
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That's it. Any other response is either a variation of these (like "resize the buffer," which is really just deferring the choice) or domain-specific logic that doesn't belong in a general streaming primitive. Web streams currently always choose Wait by default.